| Comparing the distance with the size of Jupiter, I felt like checking how
big my images were. And I stopped the equatorial mount to check how much time it took for Jupiter to go across the camera finder. It would help me in the future, too. When we talk about size of a screen or picture, we use diagonal size, but the side length is enough this time. There might be some errors or equation such as follows: I should have chosen a star on the equator but it is a little hard to find the moment it comes in and out of the camera finder. It's up to my motor nerves? Jupiter is much easier to find it. Also Jupiter is Dec. -4°55' and not so far from equator, I guess. As you know Jupiter is a planet, not a fixed star but its revolution cycle is 12years, which means moving 30degrees a year; 30°*60/365=4.9315' a day; 295.89"/86400*32=0.1095"arc in 32seconds. Besides, we can correct the difference even if Jupiter went wrong a little like the image below. (Oh, no!) First of all I have to correct it. cos6=0.99452 Well, it's not a big deal but looks corrected if reducing time a little. (Then, the correction is meaningless!! Sorry.) |
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WOW! about 6.82arc seconds! The actual elongation (Dr. Kimura's data) was 6.83arc seconds at that time. What a coincident!! The central points of Sirius-A and B are not clear so if it was long like 50pixels, it would be 7.75049"arc, a little far but not so bad. |
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